a)sin α—?
cos α=1/2
sin²α+cos²α=1
sin²α+1/4=1
sin²a=3/4
sinα=√3/2
b) cos α=√2/2
sinα—?
sin²α+cos²a=1
sin²a+1/2=1
sin²α=1/2
sinα=1/√2
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Answers & Comments
a)sin α—?
cos α=1/2
sin²α+cos²α=1
sin²α+1/4=1
sin²a=3/4
sinα=√3/2
b) cos α=√2/2
sinα—?
sin²α+cos²a=1
sin²a+1/2=1
sin²α=1/2
sinα=1/√2