Объяснение:
1. х≠7
2. 1) 2а^3/5b 2)3x(4y-1)/3xy=4y-1/y 3)(y-2)(y+2)/3(y+2)=y-2/3 4)(4-x)(4+x)/(x+4)^2=4-x/x+4
3. 1) ((x-3)×x/3x^3)-((7-x)×3)=x^2-3x-21+3x/3x^3=x^2-21/3x^3
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Answers & Comments
Объяснение:
1. х≠7
2. 1) 2а^3/5b 2)3x(4y-1)/3xy=4y-1/y 3)(y-2)(y+2)/3(y+2)=y-2/3 4)(4-x)(4+x)/(x+4)^2=4-x/x+4
3. 1) ((x-3)×x/3x^3)-((7-x)×3)=x^2-3x-21+3x/3x^3=x^2-21/3x^3