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dashakazakova18
@dashakazakova18
July 2022
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Помогите пж 4x2+y2>4xy-5
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Я112
4x2–4xy+y2=(2x–y)2
(2x–y)2
≥ 0 при любых х и у.
(2х–у)2
> –5 – верно при любых х и у.
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dashakazakova18
там 4x2 это 4 в квадрате
Я112
ааа
dashakazakova18
ага реши ещё раз пж срочно
dashakazakova18
ну
Я112
я не могу решить
dashakazakova18
блин
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Answers & Comments
(2x–y)2 ≥ 0 при любых х и у.
(2х–у)2 > –5 – верно при любых х и у.