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thew3975
@thew3975
October 2021
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Помогите пж 5 минут осталось
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Ilya27022002
Находим молекулярную массу FeS2:
Mr (FeS2) = Ar (Fe) + 2 Ar (S) = 56 + 2 * 32 = 120 г/моль
Находим массовую долю серы:
W (%) = (Ar : Mr) * 100
W (S) = (32 : 120 г/моль) * 100 = 26,67 %
Ответ : 26,67 %
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Answers & Comments
Mr (FeS2) = Ar (Fe) + 2 Ar (S) = 56 + 2 * 32 = 120 г/моль
Находим массовую долю серы:
W (%) = (Ar : Mr) * 100
W (S) = (32 : 120 г/моль) * 100 = 26,67 %
Ответ : 26,67 %