Помогите пж решить!!!!!!111!!!1!1 sin2100 + cos(-4800)

anelyaabb @anelyaabb

July 2022 1 10 Report

Помогите пж решить!!!!!!111!!!1!1
sin2100 + cos(-4800) - √3 сtg4800

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sangers1959

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Объяснение:

$sin(2100^0)+cos(-4800^0)-\sqrt{3} *ctg(4800^0)=\\=sin(360^0*6-60^0)+cos(360^0*13+120^0)-\sqrt{3}*ctg(360^0*13+120^0)=\\=-\frac{\sqrt{3} }{2} -\frac{1}{2} -\sqrt{3} *(-\frac{\sqrt{3} }{3})=-\frac{\sqrt{3} }{2}-\frac{1}{2}+1 =\frac{1}{2}-\frac{\sqrt{3} }{2} =\frac{1-\sqrt{3} }{2}.$

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