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daiv1110
@daiv1110
July 2022
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помогите ПЖ. !!!!!!!!! с задачами № 59,60,61, спасибо
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svetaprotsenko
№59
1)sqrt12=2*sqrt3
2)sqrt18=3*sqrt2
3)sqrt50=5*sqrt2
4)sqrt48=2*sqrt12
5)sqrt108=6*sqrt7
№60
1)(1/2)*sqrt24=sqrt12
2) (2/3)*sqrt45=sqrt20
3)(1,2)*sqrt300=12*sqrt3
4) (-1/7)*sqrt147=-sqrt3
5) (-1/5)*sqrt275=-sqrt11
№61
1)3*sqrt10=sqrt90
2)5*sqrt3=sqrt75
3)6*sqrt(1,5)=sqrt54
4)3*sqrt(2/3)=sqrt6
5)-5*sqrt2=-sqrt50
6)-12*sqrt(c/2)=-sqrt72c
7)(1/2)sqrt6x=sqrt(1,5x)
8)(-2/3)sqrt3y=-sqrt(4/3)
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Answers & Comments
1)sqrt12=2*sqrt3
2)sqrt18=3*sqrt2
3)sqrt50=5*sqrt2
4)sqrt48=2*sqrt12
5)sqrt108=6*sqrt7
№60
1)(1/2)*sqrt24=sqrt12
2) (2/3)*sqrt45=sqrt20
3)(1,2)*sqrt300=12*sqrt3
4) (-1/7)*sqrt147=-sqrt3
5) (-1/5)*sqrt275=-sqrt11
№61
1)3*sqrt10=sqrt90
2)5*sqrt3=sqrt75
3)6*sqrt(1,5)=sqrt54
4)3*sqrt(2/3)=sqrt6
5)-5*sqrt2=-sqrt50
6)-12*sqrt(c/2)=-sqrt72c
7)(1/2)sqrt6x=sqrt(1,5x)
8)(-2/3)sqrt3y=-sqrt(4/3)