б) (x - 6x³)² = x² -12 + 36
в) (y+b)² (y-b)²= (y²-b²)²= - 2b²y² +
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б) (x - 6x³)² = x² -12
+ 36![x^{6\\} x^{6\\}](https://tex.z-dn.net/?f=x%5E%7B6%5C%5C%7D)
в) (y+b)² (y-b)²= (y²-b²)²=
- 2b²y² +![b^{4} b^{4}](https://tex.z-dn.net/?f=b%5E%7B4%7D)
Ответ: