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hana7766778776
@hana7766778776
August 2022
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помогите пж
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zinaidazina
а)
b)
c)
f)
g)
h)
i)
2 votes
Thanks 2
hana7766778776
это точно правильно?
hana7766778776
я просто не хочу наделать ошибок
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Answers & Comments
а)
b)![(5\sqrt[3]{2}} )^3=5^3*2=125*2=250 (5\sqrt[3]{2}} )^3=5^3*2=125*2=250](https://tex.z-dn.net/?f=%285%5Csqrt%5B3%5D%7B2%7D%7D%20%29%5E3%3D5%5E3%2A2%3D125%2A2%3D250)
c)![(-2\sqrt[4]{3}} )^4=(-2)^4*3=16*3=48 (-2\sqrt[4]{3}} )^4=(-2)^4*3=16*3=48](https://tex.z-dn.net/?f=%28-2%5Csqrt%5B4%5D%7B3%7D%7D%20%29%5E4%3D%28-2%29%5E4%2A3%3D16%2A3%3D48)
f)![\sqrt[4]{(-3)^4}} +\sqrt[3]{(-3)^3}} =3-3=0 \sqrt[4]{(-3)^4}} +\sqrt[3]{(-3)^3}} =3-3=0](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28-3%29%5E4%7D%7D%20%2B%5Csqrt%5B3%5D%7B%28-3%29%5E3%7D%7D%20%3D3-3%3D0)
g)![\sqrt[6]{(-8)^2}=\sqrt[6]{64}=\sqrt[6]{2^6}=2 \sqrt[6]{(-8)^2}=\sqrt[6]{64}=\sqrt[6]{2^6}=2](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B%28-8%29%5E2%7D%3D%5Csqrt%5B6%5D%7B64%7D%3D%5Csqrt%5B6%5D%7B2%5E6%7D%3D2)
h)![2\sqrt[3]{(-4)^3}=2*(-4)=-8 2\sqrt[3]{(-4)^3}=2*(-4)=-8](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B%28-4%29%5E3%7D%3D2%2A%28-4%29%3D-8)
i)