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shs55906132
@shs55906132
July 2022
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Помогите пж: xy*x^2+xy*x^2y
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galymzhanovap
Ответ:
х^3у+х^3у^2
х^3у*(1+у)
1 votes
Thanks 2
shs55906132
Спасибо огромное
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Answers & Comments
Ответ:
х^3у+х^3у^2
х^3у*(1+у)