1)угол СDB=180-120=60
2)уг.СDB+уг.С+уг.CBD=180
60+22х+4+15х+5=180
37х=111
х=3
уг.C=15*3+5=50°
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
1)угол СDB=180-120=60
2)уг.СDB+уг.С+уг.CBD=180
60+22х+4+15х+5=180
37х=111
х=3
уг.C=15*3+5=50°