Ответ:
1)M(cucl2)=M(cu)+2*M(cl)=64+71=135
2)2M(h2o)=4*M(h)+2*M(o)=4+36=40
3)M(cucl2*2 h20)=135*40=5400
4)ω(Cu)=64/135*100%=47%
ω(Cl)=100%-47%=53%
5)Mr(H2O)=1•2+16=18 W(H2)=1•2/18=0,11=11% W(O)=16/18=0,89=89%
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Ответ:
1)M(cucl2)=M(cu)+2*M(cl)=64+71=135
2)2M(h2o)=4*M(h)+2*M(o)=4+36=40
3)M(cucl2*2 h20)=135*40=5400
4)ω(Cu)=64/135*100%=47%
ω(Cl)=100%-47%=53%
5)Mr(H2O)=1•2+16=18 W(H2)=1•2/18=0,11=11% W(O)=16/18=0,89=89%