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Delya08
@Delya08
July 2022
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Помогите пжл неравенство решить
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sangers1959
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(x²-5x+4)/log₂(x-1)≥0
x²-5x+4=x²-x-4x+4=x(x-1)-4(x-1)=(x-4)(x-1) ⇒
(x-1)(x-4)/log₂(x-1)≥0
x-1>0 x>1
x-4≥0 x≥4
log₂(x-1)>0 x-1>2⁰ x-1>1 x>2 ⇒ x∈[4;+∞)
x-1>0 x>1
x-4≤0 x≤4
log₂(x-1)<0 x-1<2⁰ x-1<1 x<2 ⇒ x∈(1;2)
Ответ: х∈(1;2)U[4;+∞).
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Answers & Comments
Verified answer
(x²-5x+4)/log₂(x-1)≥0x²-5x+4=x²-x-4x+4=x(x-1)-4(x-1)=(x-4)(x-1) ⇒
(x-1)(x-4)/log₂(x-1)≥0
x-1>0 x>1
x-4≥0 x≥4
log₂(x-1)>0 x-1>2⁰ x-1>1 x>2 ⇒ x∈[4;+∞)
x-1>0 x>1
x-4≤0 x≤4
log₂(x-1)<0 x-1<2⁰ x-1<1 x<2 ⇒ x∈(1;2)
Ответ: х∈(1;2)U[4;+∞).