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alog08
@alog08
June 2022
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Помогите ! Рассчитайте массовую долю кислорода в следующем оксиде N2O5.
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mrvladimir2
Verified answer
Mr(N₂O₅) = 108
ω(O)=80/108=0.7407 = 74,07%
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Verified answer
Mr(N₂O₅) = 108ω(O)=80/108=0.7407 = 74,07%