Помогите решить 1 и 4.Буду благодарен.. Created by donik06. algebra-ru

Помогите решить 1 и 4.Буду благодарен...

donik06 @donik06

July 2022 2 6 Report

Помогите решить 1 и 4.Буду благодарен.

NeZeRAvix

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задание решено $\checkmark$

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sedinalana 1
x²-6x+8=0
x1+x2=6 U x1*x2=8⇒x1=2 U x2=4
x²-3x+2=0
x1+x2=3 U x1*x2=2⇒⇒x1=1 U x2=2
(x-2)(x-4)/(x-1)-(x-4)/(x-1)(x-2)≤0
[(x-4)(x-2)²-(x-4)]/(x-1)(x-2)≤0
(x-4)(x²-4x+4-1)/(x-1)(x-2)≤0
(x-4)(x²-4x+3)/(x-2)(x-1)≤0
x²-4x+3=0
x1+x2=4 U x1*x2=3⇒x=1 U x=3
(x-4)(x-1)(x-3)/(x-1)(x-2)≤0
(x-4)(x-3)/(x-2)≤0,x≠1
_ _ + _ +
------(1)-----------(2)-------------[3]-----------[4]-------
x∈(-∞;1) U (1;2) U [3;4]
4
(x-1,8)²(x-1,5)≤0
_ + +
--------[1,5]-------------[1,8]------------
x∈(-∞;1,5] U {1,8}

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