August 2021 0 4 Report
Помогите решить! 1) В геометрической прогрессии q=2, S7=635. Найдите ее шестой член.
2) Сумма первых трех членов возрастающей геометрической прогрессии равна 13, а их произведение равно 27. Вычислить сумму первых пяти членов этой прогрессии.
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.
More Questions From This User See All
pomogite reshit na naklonnoj ploskosti s uglom naklona 265 gradksov k goriz
Answer
v korobke lezhali 23 shara krasnye belye i chernye belyh sharov v 11 raz bolshe
Answer
chto v kletke podvergaetsya bolee bystromu rasshepleniyu belki ili uglevody otvet
Answer
pochemu pri nedostatke povarennoj soli organizm cheloveka pogibaet
Answer
2x^2 - 3xy-19y^2 = 25, x^2-6y^2 = 250...
Answer
storony treugolnika ravny 10 12 15 sm najdite dliny srednih linij etogo treu
Answer
napishite tochnoe reshenie s otvetom
Answer
n1 2 najdite summu pyati pervyh chlenov geometricheskoj progressii dlya kotoroj b
Answer
v arifmeticheskoj progressii d2 n50 sn2650 najdite pervyj i n nyj chleny
Answer
pomogite reshit 1 najdite naturalnye chisla obrazuyushie arifmeticheskuyu progr
Answer

Helpful Links

Helpful Social

Copyright © 2024 SCHOLAR.TIPS - All rights reserved.