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РАУАН221
@РАУАН221
June 2022
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Помогите решить 1) x^2+2x-3=2x+6 ; 2) (x-1)^2+(x+1)^2=2 ; 3) 3x^2-12=0 ; 4) 3x^2+7=2x+7 ; 5) (x-2)^2+(x+2)^2=8
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Answers & Comments
ilyaska1
1)x²+2x-3-2x-6=0
x²-9=0
(x-3)(x+3)=0
x₁=3
x₂=-3
3)3x²-12=0÷3
x²-4=0
(x-2)(x+2)=0
x₁=2
x₂=-2
4)3x²+7-2x-7=0
x(3x-2)=0
x=0 или 3x-2=0
x₁=0
x₂=2÷3
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Answers & Comments
x²-9=0
(x-3)(x+3)=0
x₁=3
x₂=-3
3)3x²-12=0÷3
x²-4=0
(x-2)(x+2)=0
x₁=2
x₂=-2
4)3x²+7-2x-7=0
x(3x-2)=0
x=0 или 3x-2=0
x₁=0
x₂=2÷3