Помогите решить 1,2,3,7,5 Срочно. Заранее спасибо.)). Created by artemetylin1. algebra-ru

1.4x²-12=04(x²-3)=0x²-3=0x²=3x₁= -√3x₂=√3Ответ: -√3; √3.2.[4x/(x-y)(x+y)] - [4(x-y)/(x+y)(x-y)]=(4x-4x+4y)/(x²-y²)=(4y)/(x²-y²)3.3x>12+11x3x-11x>12-8x>12x<12 : (-8)x< -1.55x-1<05x<1x<0.2{x< -1.5{x<0.2\\\\\\\\\\\-------- -1.5 ---------- 0.2 ------------\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\x< -1.5x∈(-∞; -1.5)5.3x²+2x-1=3x²+3x-x-1=3x(x+1)-(x+1)=(x+1)(3x-1)7.sin²α-2sinαcosα+cos²α+2sinαcosα=sin²α+cos²α=1 Реклама Реклама хэлпмии хэлпмии 4х^2-12=04х^2=12 (:4)х^2=3х=под корнем 3 Реклама Реклама Новые вопросы в Алгебра СРОЧНО!!!ДА Я 30 БАЛЛОВ первый цех изготовил на 120 деталей меньше чем второй цех сколько деталей изготовил каждый цех если вместе они изготовили 240 деталей 8 класс,срочно!1.Сократите дроби:a)6х в кубе у в квадрате / 15ху в кубеб)2б+18 / б в квадрате +18б+81в)у в квадрате -2у+1 / 1-у в квадрате2.Представьт … е в виде дроби:а)15b-2 / 10б в квадрате + 5+б / 5б в кубеб) х-3- х в квадрате -х / х+23.Докажите,что при любых допустимых значениях а переменных значение выражения не зависит от х и у:2у в квадрате / ху+2у в квадрате - 2ху-х в квадрате / х в квадрате - 4у в квадрате4.Упростите выражение:3/х+3 + 3/х в квадрате - 3х + 2х/9-х в квадрате найдите х: х : 2 1/4 - 7*х = 1 3/8 -6x+4 якщо x=5 помоги те пожалуйста Упростите 5.8, и пожалуйста можно с объяснением, а то я в инете нашла и ничего не поняла, меня прост на уроке не было в этот день Помогите решить номер 1.125 и 1.126 пожалуйста Частное 5 2/9 и 6 4/15 уменьшить на 1 2/10помогите пожалуйста В кассе было 19 монет по 2 р. и по 5 р. на общую сумму 62 р. Сколько монет каждого вида было в кассе, если x равен количеству монет по пять рублей? тема неравенство 9 клас помогите решить срочнооооооо[tex]8x + 4 > 16x - 8[/tex] Предыдущий Следующий Реклама - это не так уж плохо Реклама - это не так уж плохо Понимаем - вы пришли сюда не за рекламой. Но она помогает нам предоставлять бесплатный доступ к Знаниям. Пожалуйста, внесите наш сайт в список разрешенных. ОК, разблокирую рекламу на Знаниях! Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Помогите решить 1,2,3,7,5 Срочно. Заранее спасибо.))...

artemetylin1 @artemetylin1

October 2021 1 8 Report

Помогите решить 1,2,3,7,5 Срочно. Заранее спасибо.))

Answers & Comments

хэлпмии 1.
4x²-12=0
4(x²-3)=0
x²-3=0
x²=3
x₁= -√3
x₂=√3
Ответ: -√3; √3.

2.
[4x/(x-y)(x+y)] - [4(x-y)/(x+y)(x-y)]=(4x-4x+4y)/(x²-y²)=(4y)/(x²-y²)

3.
3x>12+11x
3x-11x>12
-8x>12
x<12 : (-8)
x< -1.5

5x-1<0
5x<1
x<0.2

{x< -1.5
{x<0.2
\\\\\\\\\\\
-------- -1.5 ---------- 0.2 ------------
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
x< -1.5
x∈(-∞; -1.5)

5.
3x²+2x-1=3x²+3x-x-1=3x(x+1)-(x+1)=(x+1)(3x-1)

7.
sin²α-2sinαcosα+cos²α+2sinαcosα=sin²α+cos²α=1