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Valeri2002
@Valeri2002
July 2022
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помогите решить 13,14 пожалуйста,прошу.
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хихимик
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13.M( брома) = 265,6 * 10⁻²⁴ * 6,02* 10²³ = 160 г .Ar(Br) = 80.160/80 = 2 .Ответ: 2 атома брома в молекуле.14.KxBryOzx : y : z = 23,3/39 : 47,90/80 : 28,75/16 = 0,6 : 0,6 : 1,8 = 1 : 1 : 3.KBrO₃
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Valeri2002
спасибо огромное
Valeri2002
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Answers & Comments
Verified answer
13.M( брома) = 265,6 * 10⁻²⁴ * 6,02* 10²³ = 160 г .Ar(Br) = 80.160/80 = 2 .Ответ: 2 атома брома в молекуле.14.KxBryOzx : y : z = 23,3/39 : 47,90/80 : 28,75/16 = 0,6 : 0,6 : 1,8 = 1 : 1 : 3.KBrO₃