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DomnikaMaksimova
@DomnikaMaksimova
August 2022
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помогите решить 2 примера (подробное решение)
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sedinalana
Verified answer
755
1)9a-25/a=(9a²-25)/a
2)3√a-5/√a=(3a-5)/√a
3)(9a²-25)/a:(3a-5)/√a=(3a-5)(3a+5)/a*√a/(3a-5)=(3a+5)/√a
4)a+7 +10/a=(a²+7a+10)/a
5)√a+2/√a=(a+2)/√a
6)(a²+7a+10)/a:(a+2)/√a=(a+5)(a+2)/a*√a/(a+2)=(a+5)/√a
7)(3a+5)/√a-(a+5)/√a=(3a+5-a-5)/√a=2a/√a=2√a
8)(2√a)^4=16a²
756
1)3∛b/∛b(b-9)+1:(b-9)/√b=3/(b-9)+√b/(b-9)=(√b+3)/(√b-3)(3+√b)=1/(√b-3)
2)[1/(√b-3)]^-2=(√b-3)²
3)(√b-3)²-[(b+9)²)]^1/2=b-6√b+9-b-9=-6√6
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DomnikaMaksimova
в 756 примере ответ должен получится : -6√b
kisonix
............................
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Answers & Comments
Verified answer
7551)9a-25/a=(9a²-25)/a
2)3√a-5/√a=(3a-5)/√a
3)(9a²-25)/a:(3a-5)/√a=(3a-5)(3a+5)/a*√a/(3a-5)=(3a+5)/√a
4)a+7 +10/a=(a²+7a+10)/a
5)√a+2/√a=(a+2)/√a
6)(a²+7a+10)/a:(a+2)/√a=(a+5)(a+2)/a*√a/(a+2)=(a+5)/√a
7)(3a+5)/√a-(a+5)/√a=(3a+5-a-5)/√a=2a/√a=2√a
8)(2√a)^4=16a²
756
1)3∛b/∛b(b-9)+1:(b-9)/√b=3/(b-9)+√b/(b-9)=(√b+3)/(√b-3)(3+√b)=1/(√b-3)
2)[1/(√b-3)]^-2=(√b-3)²
3)(√b-3)²-[(b+9)²)]^1/2=b-6√b+9-b-9=-6√6