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res234
@res234
July 2022
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Помогите решить 2(в),3,4(Б),5
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tatianahumanity
2⁴ˣ-7·4ˣ·3ˣ⁻¹+4·3²ˣ⁻¹=0
4²ˣ-7·4ˣ·3ˣ/3+4·3²ˣ/3=0
3·4²ˣ-7·4ˣ·3ˣ+4·3²ˣ=0
Заменим 3ˣ=а, 4ˣ=в
3·в²-4ав-3ав+4·а²=0
(3в²-3ав)-(4ав-4а²)=0
3в(в-а)-4а(в-а)=0
(3в-4а)·(в-а)=0
в-а=0, в=а, 4ˣ=3ˣ, х=0
3в-4а=0, 3в=4а. 3·4ˣ=4·3ˣ, 3/4=(3/4)ˣ, х=1
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Answers & Comments
4²ˣ-7·4ˣ·3ˣ/3+4·3²ˣ/3=0
3·4²ˣ-7·4ˣ·3ˣ+4·3²ˣ=0
Заменим 3ˣ=а, 4ˣ=в
3·в²-4ав-3ав+4·а²=0
(3в²-3ав)-(4ав-4а²)=0
3в(в-а)-4а(в-а)=0
(3в-4а)·(в-а)=0
в-а=0, в=а, 4ˣ=3ˣ, х=0
3в-4а=0, 3в=4а. 3·4ˣ=4·3ˣ, 3/4=(3/4)ˣ, х=1