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dimasimakin97
@dimasimakin97
July 2022
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Помогите решить
(2x+1)³-4х²(2х+3)-7=0
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Sergio82
Раскрываем скобки:
8x^3 +3*(2x)^2*1 + 3*2x*1^2 +1^3 - 8x^3 - 12x^2 - 7 = 0
12x^2 + 6x + 1 - 12x^2 - 7 = 0
6x = 6. Делим на 6
Ответ: x = 1
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Thanks 0
polozkova2017
8x^3+3-8x^3-12x^2-7=0
-12x^2-4=0
a=-12;b=0;c=-4
Д=b^2-4ac=0-192=-192 нет решения
0 votes
Thanks 0
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Answers & Comments
8x^3 +3*(2x)^2*1 + 3*2x*1^2 +1^3 - 8x^3 - 12x^2 - 7 = 0
12x^2 + 6x + 1 - 12x^2 - 7 = 0
6x = 6. Делим на 6
Ответ: x = 1
-12x^2-4=0
a=-12;b=0;c=-4
Д=b^2-4ac=0-192=-192 нет решения