Помогите решить
(2x+5) во второй степени + (5x-3) во второй степени =75+2x
(2x+5) во второй степени + (5x-3) во второй степени =75+2x
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4х^2+20х+25+25х^2-30х++9=75+2х
4х^2+20х+25+25х^2-30х+
+9-75-2х=0
29х^2-12х-41=0
D=b^2-4ac=(-12)^2-4*29*
*(-41)=144+4756=4900, 70
X=12-70/58=-1
X=12+70/58=82/58=41/29