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BlueWater
@BlueWater
July 2022
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Помогите решить 3 и 4 задачу!
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ulusa4eva
3. cmt1-t2+лямбда*m
2100дж/кг*градус Цельсия*1,5кг*20градусов+333000дж/кг*1,5кг=63.000+499500=562500дж
2 V2=4литра=4кг
Q1=Q2
C1m1tоб-t1=c1m2t2-tоб
Тогда m1=c1m2t2-tоб/с1tоб-t1
4200*4кг*60/4200*20
А дальше решишь
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Answers & Comments
2100дж/кг*градус Цельсия*1,5кг*20градусов+333000дж/кг*1,5кг=63.000+499500=562500дж
2 V2=4литра=4кг
Q1=Q2
C1m1tоб-t1=c1m2t2-tоб
Тогда m1=c1m2t2-tоб/с1tоб-t1
4200*4кг*60/4200*20
А дальше решишь