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itani99
@itani99
August 2021
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Помогите решить 3 задание
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pomoshnik09
У=4*х^(-1/3)+cos(2x-1)-(x-3)/(x-2)
y`=-4/3x^-4/3-sin(2x-1)*(2x-1)`-((x-3)`*(x-2)-(x-3)*(x-2)`/(x-2)^2)=
=-4/(3*x∛x)-2sin(2x-1)-(x-2-x+3)/(x-2)²=-4/(3x∛x)-2sin(2x-1)-(1/(x-2)²
2)y`=e^(x-2)-1/2√1/x+5)+7cos7x=e^(x-2)-√x+5)/2+7cos7x
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Answers & Comments
y`=-4/3x^-4/3-sin(2x-1)*(2x-1)`-((x-3)`*(x-2)-(x-3)*(x-2)`/(x-2)^2)=
=-4/(3*x∛x)-2sin(2x-1)-(x-2-x+3)/(x-2)²=-4/(3x∛x)-2sin(2x-1)-(1/(x-2)²
2)y`=e^(x-2)-1/2√1/x+5)+7cos7x=e^(x-2)-√x+5)/2+7cos7x