А12=5 кДжA12=2*po*2*Vo=4po*Vo
Qx=Q23=ΔU+A32=(3/2)*(2po*3Vo - po*Vo) + 3*po*Vo=21/8*A21
Qx==13 кДж
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А12=5 кДж
A12=2*po*2*Vo=4po*Vo
Qx=Q23=ΔU+A32=(3/2)*(2po*3Vo - po*Vo) + 3*po*Vo=21/8*A21
Qx==13 кДж