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ася992
@ася992
August 2022
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Помогите решить
4^x2+2-9*2^x2+2+8=0
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rubilovalex
(2^x^2+2)^2-9*2^x^2+2+8=0; 2^x^2+2=a. получаем: a^2-9a+8=0; D(-9)^2-4*8=81-32=49; a1=(9-7)/2, a2=(9+7)/2. a1=1, a2=8. 2^x^2+2=1, 2^x^2+2=2^0, x^2+2=0(корней нет). 2^x^2+2=8, 2^x^2+2=2^3; x^2+2=3; x^2=1, x1= -1, x2=1. Ответ: x1= -1, x2=1.
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rubilovalex
будут вопросы по решению, пишите.
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