Помогите решить 5 и 6 задание. Created by kirilukm992. algebra-ru

Помогите решить 5 и 6 задание...

kirilukm992 @kirilukm992

July 2022 1 10 Report

Помогите решить 5 и 6 задание

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govorukha

Объяснение:

$\frac{72 {a}^{3}b }{c} \div (27 {a}^{2} b) = \frac{72 {a}^{3}b }{c} \times \frac{1}{27 {a}^{2}b} = \frac{72 {a}^{3} }{c} \times \frac{1}{ {27a}^{2} } = \frac{72 {a}^{3} }{ {27a}^{2} c} = \frac{8a}{3c}$

$\frac{ {4a}^{2} - 1 }{ {a}^{2} - 9 } \div \frac{10a + 5}{a + 3} = \frac{(2a - 1) \times (2a + 1)}{(a - 3) \times (a + 3)} \times \frac{a + 3}{10a + 5} = \frac{(2a - 1) \times (2a + 1)}{(a - 3)} \times \frac{1}{5(2a + 1)} = \frac{(2a - 1)}{(a - 3)} \times \frac{1}{5} = \frac{(2a - 1)}{5(a - 3)} = \frac{2a - 1}{5a - 15}$

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