Ответ:
Объяснение:
x=1+y
(1+y)^2+y^2=25
1+2y+y^2+y^2=25
1+2y+2y^2=25
2y^2+2y-24=0
D = b2 - 4ac = 22 - 4·2·(-24) = 4 + 192 = 196
y1 = (-2 - √196)/2·2 = -16/ 4 = -4
y2 = (-2 + √196)/2·2 = 12 /4 = 3
x1=1-4=-3
x2=1+3=4
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Ответ:
Объяснение:
x=1+y
(1+y)^2+y^2=25
1+2y+y^2+y^2=25
1+2y+2y^2=25
2y^2+2y-24=0
D = b2 - 4ac = 22 - 4·2·(-24) = 4 + 192 = 196
y1 = (-2 - √196)/2·2 = -16/ 4 = -4
y2 = (-2 + √196)/2·2 = 12 /4 = 3
x1=1-4=-3
x2=1+3=4