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licey50
@licey50
March 2022
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помогите решить 7 номер
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Meyateus
Вот подробное решение.
1 votes
Thanks 0
licey50
спасибо
Meyateus
Без проблем
Bergo
(m+1/m - 1/m-m^2)*(m - m^2/m-1)^-1 =
-1
1) m+1/m - 1/m-m^2 = m+1/m - 1/m(1-m) = m+1/m + 1/m(m-1) = m^2-1+1/m(m-1) = m^2/m(m-1)=m/m-1
2) (m - m^2/m-1)^-1 = (m^2-m-m^2/m-1)^-1 = (-m/m-1)^-1 = - 1/m/m-1 = - m-1/m
3) m/m-1 * -(m-1/m) = - m(m-1)/m(m-1)=
-1
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Answers & Comments
1) m+1/m - 1/m-m^2 = m+1/m - 1/m(1-m) = m+1/m + 1/m(m-1) = m^2-1+1/m(m-1) = m^2/m(m-1)=m/m-1
2) (m - m^2/m-1)^-1 = (m^2-m-m^2/m-1)^-1 = (-m/m-1)^-1 = - 1/m/m-1 = - m-1/m
3) m/m-1 * -(m-1/m) = - m(m-1)/m(m-1)= -1