Помогите решить А7, А8, А9 ^^. Created by stepuriata. algebra-ru

Помогите решить А7, А8, А9 ^^...

stepuriata @stepuriata

September 2021 1 14 Report

Помогите решить А7, А8, А9 ^^

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sedinalana

Verified answer

A7
(a²-ab)/[b(a²+b²)]-2a²/[b²(b-a)+a²(b-a)]=(a²-ab)/[b(a²+b²)]-2a²/[(b²+a²)(b-a)]=
=(a²b-a³-ab²+a²b-2a²b)/[b(b-a)(a²+b²)]=-a(a²+b²)/[b(b-a)(a²+b²)]=
=-a/[b(b-a)]=a/[b(a-b)]
Ответ 3
А8
1)|2x-3|≥3
[2x-3≤-3⇒2x≤0⇒x≤0
[2x-3≥3⇒2x≥6⇒x≥3
2)|2x-3|<7
-7<2x-3<7
-4<2x<10
-2<x<5
x∈(-2;0] U [3;5)
(-1+0+3+4)/4=6/4=3/2
Ответ 2
А9
AB=4,BB1=3⇒AB1=√(AB²+BB1²)=√(16+9)=√25=5
AD1=AB1=5
B1D1=√(A1B1²+A1D1²)=√(16+16)=√32=4√2
ΔB1AD1-равнобедренный ,высота равна √(AB1²+(B1D1/2)²)=
=√(25-8)=√17
S(B1AD1)=1/2*4√2*√17=2√34
Ответ 1

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