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steamnovac
@steamnovac
July 2022
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Помогите решить!!!
Для функции f(x)=cos3x найдите первообразную, график которой проходит через точку А(0;0)
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paradiseva
Verified answer
F(x) = 1/3 * sin(x) + C
0 = 1/3 * sin 0 + C
C = 0
F(x) = 1/3 * sin(x)
1 votes
Thanks 2
mikael2
Z=3x dx=dz/3 1/3∫coszdz=sinz/3+c=sin3x/3+C
A(0;0) sin0/3+C=0 0+C=0 C=0
F(x)=sin3x/3
1 votes
Thanks 1
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Answers & Comments
Verified answer
F(x) = 1/3 * sin(x) + C0 = 1/3 * sin 0 + C
C = 0
F(x) = 1/3 * sin(x)
A(0;0) sin0/3+C=0 0+C=0 C=0
F(x)=sin3x/3