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Ответ:

Пошаговое объяснение:

6. tg(a) = y'(x_0) = e^(x_0) = e^0 = 1

a = 45°

7. y' = 2x

1) x1 = 1

k = y'(x1) = 2*1 = 2

2) x2 = -1

k = 2 * (-1) = -2

3) x3 = 2

k = 2 * 2 = 4

4) x4 = -2

k = 2 * (-2) = -4

8.

y' = (4-2x)/4 = 1 - 0,5x

1) x1 = 0

tg(a1) = 1 - 0 = 1

a1 = 45°

2) x2 = 2

tg(a2) = 1 - 1 = 0

a2 = 0° = > прямая параллельна оси Ох

3) x3 = 4

tg(a3) = 1 - 2 = -1

a3 = 135°