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Angelika13121997a
@Angelika13121997a
July 2022
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помогите решить это уравнение,пожалуйста!
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nKrynka
Решение
(2x)^(1/4) + (32x)^(1/4) + (162)^(1/4) = 6
(2x)^(1/4) + [16*(2x)]^(1/4) + [81*(2x])^(1/4) = 6
[(2x)^(1/4)]*(1 + 4 + 9) = 6
14*[(2x)^(1/4)] = 6
(2x)^(1/4) = 6/14
(2x)^(1/4) = 2/7
[(2x)^(1/4)]⁴ = (2/7)⁴
2x = 16/2401
x = 8/2401
1 votes
Thanks 1
Angelika13121997a
спасибо!
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Answers & Comments
(2x)^(1/4) + (32x)^(1/4) + (162)^(1/4) = 6
(2x)^(1/4) + [16*(2x)]^(1/4) + [81*(2x])^(1/4) = 6
[(2x)^(1/4)]*(1 + 4 + 9) = 6
14*[(2x)^(1/4)] = 6
(2x)^(1/4) = 6/14
(2x)^(1/4) = 2/7
[(2x)^(1/4)]⁴ = (2/7)⁴
2x = 16/2401
x = 8/2401