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ksenya221122
@ksenya221122
June 2022
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sharadi
Verified answer
И) log₂x = t ( ОДЗ: x > 0)
t² -3t +2 = 0
по т. Виета корни 2 и 1
log₂x = 2 log₂x = 1
x = 4 x = 2
г) 2х(2х +а) - х(2х -а) = 5а
4х² +2ах -2ах +ха = 5а
4х² +ха -5а = 0
D = b² -4ac = a² -4*4*(-5a) = 81a²
x₁ = (-a+9a)/8 = а
х₂ =(-а -9а)/8 = -10а/8 = -5а/4
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Answers & Comments
Verified answer
И) log₂x = t ( ОДЗ: x > 0)t² -3t +2 = 0
по т. Виета корни 2 и 1
log₂x = 2 log₂x = 1
x = 4 x = 2
г) 2х(2х +а) - х(2х -а) = 5а
4х² +2ах -2ах +ха = 5а
4х² +ха -5а = 0
D = b² -4ac = a² -4*4*(-5a) = 81a²
x₁ = (-a+9a)/8 = а
х₂ =(-а -9а)/8 = -10а/8 = -5а/4