(x+1)√(x²-6x+17) = 3x+3
Одз x²-6x+17>=0 D=36 - 4*17 <0 все значения
(x+1)√(x²-6x+17) - 3(x+1) = 0
(x+1)(√(x²-6x+17) - 3) = 0
x=-1
√(x²-6x+17) = 3
x²-6x+17 = 9
x²-6x+8 = 0
D=36 - 32 = 4
x12=(6+-2)/2 = 2 4
ответ x={-1 2 4}
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(x+1)√(x²-6x+17) = 3x+3
Одз x²-6x+17>=0 D=36 - 4*17 <0 все значения
(x+1)√(x²-6x+17) - 3(x+1) = 0
(x+1)(√(x²-6x+17) - 3) = 0
x=-1
√(x²-6x+17) = 3
x²-6x+17 = 9
x²-6x+8 = 0
D=36 - 32 = 4
x12=(6+-2)/2 = 2 4
ответ x={-1 2 4}