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санёк200014456
@санёк200014456
July 2022
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помогите решить карточку задания 3 , 4.
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DariosI
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3. BC=8x
AO=5x
AC=BD=2*5x=10x поскольку ABCD прямоугольник
CD=18
CD²=BD²-BC²
18²=100x²-64x²
324=36x²
x²=9
x=3
BC=3*8=24
Pabcd=2(24+18)=2*42=84
4.
sin A=BE/AB
sin 30=BE/20
BE/20=1/2
BE=10
AE²=AB²-EB²
AE=√(20²-10²)=√300=10√3
AD=10√3+12√3=22√3
S=BE*AD=22√3*10=220√2
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Answers & Comments
Verified answer
3. BC=8xAO=5x
AC=BD=2*5x=10x поскольку ABCD прямоугольник
CD=18
CD²=BD²-BC²
18²=100x²-64x²
324=36x²
x²=9
x=3
BC=3*8=24
Pabcd=2(24+18)=2*42=84
4.
sin A=BE/AB
sin 30=BE/20
BE/20=1/2
BE=10
AE²=AB²-EB²
AE=√(20²-10²)=√300=10√3
AD=10√3+12√3=22√3
S=BE*AD=22√3*10=220√2