помогите решить логарифмическое неравенство, желательно подробно :-). Created by lola247. algebra-ru

ОДЗ: x+1>0 x> -1log₂(x+1)-3log₂(x+1)≥ -2-2log₂ (x+1) ≥ -2log₂ (x+1) ≤ 1x+1 ≤ 2¹x+1 ≤ 2x ≤ 2-1x ≤ 1{x > -1{x ≤ 1x∈(-1; 1]Ответ: (-1; 1].sangers1959sangers1959Log₂(x+1)-3*log₂(x+1)≥-2ОДЗ: х+1>0 x>-1-2*log₂(x+1)≥-2 I÷(-2)log₂(x+1)≤1log₂(x+1)≤log₂2x+1≤2x≤1Ответ: x∈(-1;1].Новые вопросы в Алгебрапомогите пожалуйста решить методом сложения Помогите решить. х=-1 у=5 то 2х+9у-7Помогите решить. х=-1 у=5 то 2х+9у-7Помогите решить. х÷х+9=14ПЛС М+ПОМОГИТЕ, ДАМС КОРОНУ И МНОГО 30 БАЛЛОВ(Нужно объяснение)557,559 номера. Если возможно,с решением Разложить на множетелиy^8-y^4+4y^2-4Дайте відповідь з рішенням будь ласка(557,559)1) 3 1/9 : 2 1/3 - 2 5/6 =28/9 * 3/7 - 17/6=4/3-17/6= 8/6-17/6=-3/2=-1.5как он получил -3/2Іван зірвав на клумбі 8 нарцисів та 4 тюльпани. Скільки всього існуєспособів вибору із цих квітів 3 нарцисів та 2 тюльпанів для букета?ПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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помогите решить логарифмическое неравенство, желательно подробно :-)...

lola247 @lola247

August 2022 1 1 Report

помогите решить логарифмическое неравенство, желательно подробно :-)

Answers & Comments

m11m

Verified answer

ОДЗ: x+1>0
x> -1

log₂(x+1)-3log₂(x+1)≥ -2
-2log₂ (x+1) ≥ -2
log₂ (x+1) ≤ 1
x+1 ≤ 2¹
x+1 ≤ 2
x ≤ 2-1
x ≤ 1

{x > -1
{x ≤ 1

x∈(-1; 1]

Ответ: (-1; 1].