Ответ:

2)4^2(1+log4 5)+4^log2 \/3+log8 125=

4^2+2log4 5+4^log2 \/3+log2^3 125

16×4^log4 25+4^log2 \/3+1/3log2 125

16×25+2^2(log2 \/3+log2 5

400+2^2log2 \/3+2log2 5

400+2^log2 3+log2 25

400+3×25=400+75=475