Помогите решить (начала тригонометрии). Created by pmgirl. algebra-ru

Помогите решить (начала тригонометрии)...

pmgirl @pmgirl

July 2022 1 1 Report

Помогите решить (начала тригонометрии)

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oganesbagoyan

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8)    | cos402° - sin41° | = | cos(360°+42°) - sin41° | = | cos42° - sin41° | =
  | sin48° - sin41° | =  sin48° - sin41° =  sin48° - cos49° → 3 .
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9)
tq(π -α) + ctqα =5 .
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(tq²α +ctq²α) -?
т.к.  tq(π -α) = - tqα следовательно   tq(π -α) + ctqα =5 ⇔ ctqα - tqα =5 .
tq²α +ctq²α =tq²α - 2tqα*ctqα +ctq²α +2tqα*ctqα = (ctqα - tqα)² +2tqα*ctqα =
5² +2 =27 . → 5 .
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10)
sin105° =sin(60° +45°) =sin60°*cos45°+ cos60°*sin45° =
(√3/ 2)*(√2/ 2)+ (1/2)*(√2/ 2) = (√6 + √2) /4. → 1 .

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pmgirl Большое спасибо!!

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