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KXD
@KXD
October 2021
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Помогите решить, не совсем поняла тему(
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математик2011
Запишем уравнения касательной в общем виде: y = y₀ + y'(x₀)(x - x₀)
х₀ = 3
у₀ = 3/(3-2) = 3
y' = х'(х-2) - х(х-2)'/(х-2)² = (х-2-х)/(х-2)² = -2/(х-2)²
y'(x₀) = -2/1 = -2
у= 3 - 2(х-3) = 3 - 2х +6 = 9 - 2х
Ответ: у=9-2х
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Answers & Comments
х₀ = 3
у₀ = 3/(3-2) = 3
y' = х'(х-2) - х(х-2)'/(х-2)² = (х-2-х)/(х-2)² = -2/(х-2)²
y'(x₀) = -2/1 = -2
у= 3 - 2(х-3) = 3 - 2х +6 = 9 - 2х
Ответ: у=9-2х