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nvolnov123
@nvolnov123
August 2022
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Помогите решить неравенства
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wejde
Verified answer
X²-4>0
(x-2)(x+2)>0
x∈(-∞;-2)∪(2;+∞)
x²-4=0
(x-2)(x+2)=0
x=-2
x=2
4-x²>0
(2-x)(2+x)>0
x∈(-2;2)
x²+7x=0
x(x+7)=0
x=0
x=-7
x²+7x≥0
x(x+7)≥0
x∈(-∞;-7]∪[0;+∞)
x²>7x
x²-7x>0
x(x-7)>0
x∈(-∞;0)∪(7;+∞)
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Answers & Comments
Verified answer
X²-4>0(x-2)(x+2)>0
x∈(-∞;-2)∪(2;+∞)
x²-4=0
(x-2)(x+2)=0
x=-2
x=2
4-x²>0
(2-x)(2+x)>0
x∈(-2;2)
x²+7x=0
x(x+7)=0
x=0
x=-7
x²+7x≥0
x(x+7)≥0
x∈(-∞;-7]∪[0;+∞)
x²>7x
x²-7x>0
x(x-7)>0
x∈(-∞;0)∪(7;+∞)