ОДЗ:Х ≠ 2
(Х-10)(2-Х)/(2-Х)=2-Х
Х-10=2-Х
2Х=12
Х=6
Х∈(6:+∞)
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ОДЗ:Х ≠ 2
(Х-10)(2-Х)/(2-Х)=2-Х
Х-10=2-Х
2Х=12
Х=6
Х∈(6:+∞)