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trabca
@trabca
August 2021
2
12
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помогите решить :номера 1,2
разложите на множители очень нужно помогите умоляю
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knopkotik
Вот номер 1 а второй решай сам там все элементарно просто
1 votes
Thanks 1
Lesben
1)2xˇ2-8=2(xˇ2-4)=2.(x+2)(x-2)
18-2yˇ2=2(9-yˇ2)=2.(3+y)(3-y)
ktˇ2-k=k(tˇ2-1)=k.(t+1)(t-1)
3cˇ2-3xˇ2 = 3.(cˇ2-xˇ2)=c(c+x)(c-x)
xˇ3-4x=x(xˇ2-4)=x(x+2)(x-2)
32aˇ3-2a=2a(16aˇ2 -1)=2a(4a+1)(4a-1)
2)2uˇ3-2vˇ3=2(uˇ3-vˇ3)=2.(u-v)(uˇ2 +uv +vˇ2)
3zˇ3+3wˇ3=3(zˇ3+wˇ3)=3.(z+w)(zˇ2-zw+wˇ2)
nxˇ3+nzˇ3=ń(xˇ3+zˇ3)=n(x+z)(xˇ2-xz+zˇ2)
wˇ4-w=w(wˇ3-1)=w(w-1)(wˇ2+w+1)
zˇ4+8z= z(zˇ3+8)=z(z+2)(zˇ2-z.2+4)
xˇ4-16zˇ4=(xˇ2+4zˇ2)(xˇ2-4zˇ2=(xˇ2+4zˇ2)(x+2z)(x-2z)
81-kˇ4=3ˇ4-kˇ4=(9+kˇ2)(9-kˇ2)=(9+kˇ2)(3+k)(3-k)
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Answers & Comments
18-2yˇ2=2(9-yˇ2)=2.(3+y)(3-y)
ktˇ2-k=k(tˇ2-1)=k.(t+1)(t-1)
3cˇ2-3xˇ2 = 3.(cˇ2-xˇ2)=c(c+x)(c-x)
xˇ3-4x=x(xˇ2-4)=x(x+2)(x-2)
32aˇ3-2a=2a(16aˇ2 -1)=2a(4a+1)(4a-1)
2)2uˇ3-2vˇ3=2(uˇ3-vˇ3)=2.(u-v)(uˇ2 +uv +vˇ2)
3zˇ3+3wˇ3=3(zˇ3+wˇ3)=3.(z+w)(zˇ2-zw+wˇ2)
nxˇ3+nzˇ3=ń(xˇ3+zˇ3)=n(x+z)(xˇ2-xz+zˇ2)
wˇ4-w=w(wˇ3-1)=w(w-1)(wˇ2+w+1)
zˇ4+8z= z(zˇ3+8)=z(z+2)(zˇ2-z.2+4)
xˇ4-16zˇ4=(xˇ2+4zˇ2)(xˇ2-4zˇ2=(xˇ2+4zˇ2)(x+2z)(x-2z)
81-kˇ4=3ˇ4-kˇ4=(9+kˇ2)(9-kˇ2)=(9+kˇ2)(3+k)(3-k)