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Nobody15
@Nobody15
August 2021
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Помогите решить обведенное тождество
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Гоша68
Verified answer
(2sin5/2a*cos3/2a)/(2sin3asina)=cosa/sina
(sin5/2acos3/2a)/(2sin3/2acos3/2asina)=cosa/sina
sin5/2a/(2sinasin3/2a)=cosa/sina
sin5/2a=2cosasin3/2a
sin5/2a=sin5/2a-sina/2
sina/2=0
a=2Пk, k∈Z
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Answers & Comments
Verified answer
(2sin5/2a*cos3/2a)/(2sin3asina)=cosa/sina(sin5/2acos3/2a)/(2sin3/2acos3/2asina)=cosa/sina
sin5/2a/(2sinasin3/2a)=cosa/sina
sin5/2a=2cosasin3/2a
sin5/2a=sin5/2a-sina/2
sina/2=0
a=2Пk, k∈Z