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098705
@098705
August 2021
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Хогвартс
1. 4Cos^2x-8Cosx+3=0
Пусть Cosx=t, тогда
4t^2-8t+3=0
D= 64-48=16
T1= 8+4/8=3/2
T2=8-4/8=1/2
|Cosx=3/2
|Cosx=1/2
X= +-arccos(3/2)+2pin
X=+-pi/3+2pin
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Answers & Comments
Пусть Cosx=t, тогда
4t^2-8t+3=0
D= 64-48=16
T1= 8+4/8=3/2
T2=8-4/8=1/2
|Cosx=3/2
|Cosx=1/2
X= +-arccos(3/2)+2pin
X=+-pi/3+2pin