x2+(5-2i)x+5(1-i)=0
D=25-20i+4i2-20+20i=5-4=1
x=(5-2i±1)/2
x=3-i
x=2-i
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x2+(5-2i)x+5(1-i)=0
D=25-20i+4i2-20+20i=5-4=1
x=(5-2i±1)/2
x=3-i
x=2-i