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dbrf1998
@dbrf1998
August 2021
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помогите решить пожалуйста
-4cos²α-4sin²α+3
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-4cos²a-4sin²a+3=-4(cos²a+sin²a)+3=-4*1+3=-4+3=-1
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Verified answer
-4cos²a-4sin²a+3=-4(cos²a+sin²a)+3=-4*1+3=-4+3=-1