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mukhamm
@mukhamm
September 2021
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Помогите решить пожалуйста, буду благодарен )
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darkangel24
3x^2+4x-16=(x-4)^2
3x^2+4x-16=x^2-8x+64
2x^2+12x-80=0
x^2+6x-40=0
D=b^2-4ac=36+160=196
x1=(-6-14)/2=-10
x2=(-6+14)/2=4
3 1/2:( 1 4/15+2 9/10)=7/2:(19/15+29/10)= 7/2:(38/30+87/30)= 7/2:125/30=7/2·30/125=21/25
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Answers & Comments
3x^2+4x-16=x^2-8x+64
2x^2+12x-80=0
x^2+6x-40=0
D=b^2-4ac=36+160=196
x1=(-6-14)/2=-10
x2=(-6+14)/2=4
3 1/2:( 1 4/15+2 9/10)=7/2:(19/15+29/10)= 7/2:(38/30+87/30)= 7/2:125/30=7/2·30/125=21/25