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alinasapar
@alinasapar
July 2022
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Помогите решить, пожалуйста:
х^4-3х^2-4=0
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Даниил18121
Х^4-3х^2-4=0
x^2=t
t^2-3t-4=0
D=b^2-4ac=9+16=25
t1,2=(-b±√D)/2a=(3±5)/2
t1=4
t2=-1
x^2=4
x1=±2
t2=-1 =>t2=√-1 - побочное решение
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Answers & Comments
x^2=t
t^2-3t-4=0
D=b^2-4ac=9+16=25
t1,2=(-b±√D)/2a=(3±5)/2
t1=4
t2=-1
x^2=4
x1=±2
t2=-1 =>t2=√-1 - побочное решение