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Dimon30555
@Dimon30555
July 2022
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помогите решить пожалуйста
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Vas61
Sin(π/2-x)=cosx
cos(π/2+x)=-sinx
-2cosx·sinx=√3cosx
-2sinx=√3
sinx=-√3/2
x=(-1)ⁿarcsin(-√3/2)+πn
arcsin(-√/2)=-arcsin√3/2=-π/3
x=(-1)ⁿ⁺¹π/3+πn n∈Z
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Answers & Comments
cos(π/2+x)=-sinx
-2cosx·sinx=√3cosx
-2sinx=√3
sinx=-√3/2
x=(-1)ⁿarcsin(-√3/2)+πn
arcsin(-√/2)=-arcsin√3/2=-π/3
x=(-1)ⁿ⁺¹π/3+πn n∈Z